python 的简单遍历问题(凑字数)

Question

问题：对xz.txt文件进行遍历的时候只能查找到最后一个字典

    shop_list = []
    while True:
        id=int(input('输入商品编号：'))
        name=input('输入商品名称：')
        a={'id':id,'name':name}
        shop_list.append(a)
        b=input('继续添加？y/n')
        if b=='y':
            continue

    else:
        print('输入的产品信息为：'+str(shop_list)+'\t')
        a=input('确实储存？')
        if a=='y':
            break
        else:
            shop_list=[]
            if a=='y':
                print('以保存')
            else:
                print('以清除')
                break
            break

def save(shop_list):
    try:
        c=open('xz.txt','a',encoding='utf-8')
    except:
        c=open('xz.txt','w',encoding='utf-8')

    for iten in shop_list:
        print(iten)
        c.write(str(iten)+'\n')
    c.close()

save(shop_list)

```python
def chioce():

    go=[]
    while True:
        a=input('输入要加入购物车的商品：')
        with open('xz.txt','r',encoding='utf-8')as c:
            shop=c.readlines()
            for item in shop:
                print(item)
                item = dict(eval(item))
                #print(shop)
                #print(item)
                a=int(a)
            if item['id']==a:
                b=item['name']
                print(b)
                go.append(b)
                break
            else:
                print('没有这个商品')
                break
    shop.append(a)
    print('购物车里有',go)
if __name__ == '__main__':
    chioce()


![img](https://img-mid.csdnimg.cn/release/static/image/mid/ask/06687669582618.png '屏幕截图 2021-08-10 195702.png')

Answer 1

        if item['id']==a:

            b=item['name']

            print(b)

            go.append(b)

            break

你这里都满足条件退出循环了，那就肯定值存进去一个了