分别输入两个数double a,b;
r = b - count * a ;
求count为几的时候,r=1.0;
例如,double a = 1.3;
double b = 3.9;
那么,count = 3
import java.util.Scanner;
public class Exg {
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
System.out.println("Pleat enter the first number!");
double a = s.nextDouble();
Scanner w = new Scanner(System.in);
System.out.println("Pleat enter the second number (larger than the first number) !");
double b = w.nextDouble();
double count=1.0;
double r;
do {
r = b- count * a;
count ++;
}while(r==1.0);
System.out.println(count);
}
}
结果大概的样子为:
Pleat enter the first number!
2.3
Pleat enter the second number (larger than the first number) !
36.9
2.0
好忧伤啊, 不论添什么数,结果都是2.0