include < stdio. h>
int main( )
{
int i,j,n=0;
for (i=1;i< =4;i++ )
for (j=1;j<=5;j++,n++) {if (n%5==0)
printf ("n");
printf ("%dt",i* j);
}
printf("n" );
return 0 ;
}
int main( )
{
int i,j,n=0;
for (i=1;i< =4;i++ )
for (j=1;j<=5;j++,n++) {if (n%5==0)
printf ("n");
printf ("%dt",i* j);
}
printf("n" );
return 0 ;
}
外层对i遍历,内层对j遍历
对于1~4中的每个i,从1~5遍历j,输出i*j的结果,每五个换一次行
即输出
1*1...1*5
2*1...2*5
....
4*1...4*5
代码运行如下
有帮助望采纳~
#include <stdio.h>
int main()
{
int i, j, n = 0;
for (i = 1; i <= 4; i++)
for (j = 1; j <= 5; j++, n++)
{
if (n % 5 == 0)
printf("\n");
printf("%d\t", i * j);
}
printf("\n");
return 0;
}