想判断数组的有效长度 然后输出阶乘的结果

Question

但是他遇到0就当成空字符了

#include <iostream>
#include<string>
using namespace std;
int main() {
    int x[1000] = { 0 }, t,ne,num=0,length = 0;
    cin >> t;
    x[0] = 1;
    for (int m = 1;m <= t; m++) {
        for (int i = 0;i < 1000;i++) {
            ne = x[i] * m+num;
            x[i] = ne % 10;
            num = ne / 10;
        }        
    }
    for (int i = 0; i < 1000;i++) {
        if (x[i] == '\0') { break; }
        else { length += 1; }
    }
    for (int i = 0;i < length;i++) {
        cout << x[length - i - 1];
    }
    return 0;
}

```c++

```

Answer 1

因为'\0'转化成ASCII码值就是0