请看一下哪里错了，ax+by=c dx+ey=f

Question

#include <stdio.h>
#include<math.h>
int main()
{
double a,b,c,d,e,f,x,y;
double det, det1, det2, ind1, ind2;
scanf("%f%f%f%f%f%f",&a,&b,&c,&d,&e,&f);
det=ae-bd;
det1=af-cd;
det2=ce-bf;
if(fabs(det)<1e-6)
if(fabs(det1)<1e-6)
{ind1=-b/a;
ind2=c/a;
printf("Infinite solution:x=%f*k+%f,k varies within R\n",ind1,ind2);}
else
printf("unsolvable\n");
else
{x=det2/det;
y=det1/det;
printf("x=%f,y=%f\n",x,y);}
return (0);
}

Answer 1

double类型读取用%lf
scanf("%f%f%f%f%f%f",&a,&b,&c,&d,&e,&f);这里的%f都改成%lf
scanf这里改完就可以了，代码如下：

#include <stdio.h>
#include <math.h>
int main()
{
    double a,b,c,d,e,f,x,y;
    double det, det1, det2, ind1, ind2;
    scanf("%lf%lf%lf%lf%lf%lf",&a,&b,&c,&d,&e,&f);

    det=a*e-b*d;
    det1=a*f-c*d;
    det2=c*e-b*f;
    if(fabs(det)<1e-6)
        if(fabs(det1)<1e-6)
        {
            ind1=-b/a;
            ind2=c/a;
            printf("Infinite solution:x=%f*k+%f,k varies within R\n",ind1,ind2);
        }
        else
            printf("unsolvable\n");
    else
    {
        x=det2/det;
        y=det1/det;
        printf("x=%f,y=%f\n",x,y);
    }
    return (0);
}