只要告诉我下列代码的是怎么得到结果的步骤就行

Question

public class Elements {

  boolean[] array1 = {false,false,false};

  int count = 0;

 void set(boolean[] arr, int x){

        arr[x] = true;

        count++;

        System.out.println(count);

  }

void func(){

  if(array1[0] && (

     array1[++count - 2] || array1 [count - 1]))

  count++;

  System.out.println("count = " + count);

}

public static void main(String[] args){

  Elements EObject1 = new Elements();

  EObject1.set(EObject1.array1, 2);

  EObject1.set(EObject1.array1, 2);

  EObject1.set(EObject1.array1, 2);

   EObject1.func();

}

}

Answer 1

EObject1.set(EObject1.array1, 2);输出1
EObject1.set(EObject1.array1, 2);输出2
EObject1.set(EObject1.array1, 2);输出3
这三句结束后，array1变成了{false,false,true},count = 3
调用EObject1.func();由于array1[0]为false
array1[0] && (array1[++count - 2] || array1[count - 1])为false不进入if语句
count仍然是3
输出"count = 3"