求数列 1 1 2 3 5 8 13 21…的前30个数

Question

用for循环语句输出斐波那契数列的前三十个数…………………………………………

Answer 1

#include <stdio.h>
int main()
{
   int a,b,c,i;
   a = 1;
   b = 1;
   printf("1 1 ");
   for(i = 2;i < 30;i++){
       c = a + b;
       printf("%d ",c);
       a = b;
       b = c;
   }
}