m0_64067309 2022-01-15 17:23 采纳率: 100%
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已结题

怎么对char[10]={0}进行u01到u10的赋值

int main()
{
char uid[10][5] = { 0 };
int salary[10], csalary[10], revenue[10], _water_electricity[10], _deductions[10];
int t_salary[10], deduction_count[10], r_salary[10];
int r_rank[10] = { 0,1,2,3,4,5,6,7,8,9 };
input_data(uid, salary, csalary, revenue, _water_electricity, _deductions);
calculate(uid, salary, csalary, revenue, _water_electricity, _deductions, t_salary, deduction_count, r_salary);
rank_r_salary(r_salary, r_rank);
rank_t_salary_id(uid, salary, csalary, revenue, _water_electricity, _deductions, t_salary, deduction_count, r_salary, r_rank);

return 0;

}

char uid1[10] = { "u01","u02","u03","u04","u05","u06","u07","u08","u09","u10" };为什么显示我初始值设定项太多

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1条回答 默认 最新

  • 秋天的毛毛虫 2022-01-16 20:40
    关注

    uid1是个char数组,不是字符串数组,
    char uid1[10] = { "u01","u02","u03","u04","u05","u06","u07","u08","u09","u10" }; 是为字符串数组初始化,类型不匹配
    char uid1[10]= {"u001"}; 这样是为字符数组初始化;
    string uid1[10] = { "u01","u02","u03","u04","u05","u06","u07","u08","u09","u10" }; 为字符串数组初始化
    char uid1[10][5] = { "u01","u02","u03","u04","u05","u06","u07","u08","u09","u10" }; 二维字符数组初始化

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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问题事件

  • 系统已结题 1月25日
  • 已采纳回答 1月17日
  • 创建了问题 1月15日

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