爬取小说时超出索引范围

Question

问题遇到的现象和发生背景

本人出于兴趣开始了python的相关学习，在跟着网课学习爬虫的过程遇到了一些问题

问题相关代码，请勿粘贴截图

def get_text(url):...if
    r = requests.get(url)
    r.encoding = 'utf-8'
    contents_All = etree.HTML(r.text)
    contents_title = contents_All.xpath('//*[@id="wrapper"]/div[4]/div[1]/div[2]/h1/text()')
    contents_word = contents_All.xpath('//*[@id="content"]/text()')
    with open(path + contents_title[0]+'.txt', "w", encoding="utf-8") as f:
        f.write(contents_word)
    print(contents_title[0], "下载成功")
    time.sleep(2)

if __name__ == '__main__':
    for url in contents_list:
        get_text(url)

运行结果及报错内容

结果：

Traceback (most recent call last):
  File "D:\pythonProject\爬虫\爬取小说\xpath.py", line 50, in <module>
    get_text(url)
  File "D:\pythonProject\爬虫\爬取小说\xpath.py", line 42, in get_text
    with open(path + contents_title[0]+'.txt', "w", encoding="utf-8") as f:
IndexError: list index out of range

Answer 1

应该是 contents_title 没匹配上
检查下你的xpath

def get_text(url):...if
    r = requests.get(url)
    r.encoding = 'utf-8'
    contents_All = etree.HTML(r.text)
    contents_title = contents_All.xpath('//*[@id="wrapper"]/div[4]/div[1]/div[2]/h1/text()')
    if len(contents_title)==1: 
        contents_word = contents_All.xpath('//*[@id="content"]/text()')
        with open(path + contents_title[0]+'.txt', "w", encoding="utf-8") as f:
            f.write(contents_word)
        print(contents_title[0], "下载成功")
    else:
        print("没找到标题，下载失败")
    time.sleep(2)