C++进制转换程序纠错

Question

#include
using namespace std;

int main()
{
int i=0,r,n,a[10];
char b[16]={'1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};
cin >> n>>r;
do{
a[i]=n%r;
n=n/r;
i++;
}while(n!=0);
for(--i;i>=0;--i)
{
n=a[i];
cout << b[n];
}
system("pause");
return 0;
}
运行结果下来是有偏差的

Answer 1

#include <iostream>
using namespace std;

int main()
{
    int i = 0, r, n, a[10];
    char b[17] = { '0', '1','2','3','4','5','6','7','8','9','A','B','C','D','E','F' };
    cin >> n >> r;
    do {
        a[i] = n % r;
        n = n / r;
        i++;
    } while (n != 0);
    for (--i; i >= 0; --i)
    {
        cout << b[a[i]];
    }
    cout << endl;
    return 0;
}

在你的代码的基础上改的，任意进制都可以转换