这个为啥运行没有姓名 咋完善？

Question

那个姓名没有运行出来，这种如何完善，求浴室收费问题，就类和对象关系

Answer 1

public class ShowerCharge {
    private int id;
    private String name;
    private double money;
    private double price=0.5;

    public ShowerCharge(int id,String name,double money,double price){
        this.id = id;
        this.name = name;
        this.money = money;
        this.price = price;
    }

    public void charge(double waterConsumption){
        double m = waterConsumption*price;
        System.out.println("姓名："+name);
        System.out.println("本次应收费："+m);
        if(money-m>0){
            money -=m;
            System.out.println("余额"+money);
        } else {
            money = 0;
            System.out.println("余额不足请充值："+(m-money));
        }
    }

    public static void main(String[] args) {
        ShowerCharge showerCharge = new ShowerCharge(1,"贾",100,0.5);
        showerCharge.charge(100);
        showerCharge.charge(100);
        showerCharge.charge(101);
    }
}