这一串代码的xpath怎么写

Question

尝试提取class=title，也就是 勿忘2020，前行2021

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    <a class="title" href="/p/f9d3626adf38">勿忘2020，前行2021</a>
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Answer 1

import re
a = re.findall(r'<a class="title".*</a>',input())
print(a)

不如用re来解决