定义复数类（Complex）,包含必要的构造函数和析构函数，重载乘法赋值运算符“*=”实现复数与整数，复数与复数之间的乘法运算，自行举例并按格式输出

Question

#要求达到的效果：
1.格式要求举例
c=2+3i
c*=5，c=10+15i
c*=4+5i,c=-7+22i
2.要求使用转换构造函数把整数转换为复数后进行运算
3.遇到的问题：数学逻辑不清晰
4.

using namespace std;

class Complex
{public:
Complex(){real=0;imag=0;}//定义构造函数
Complex(double r,double i){real=r;imag=i;}//构造函数重载
Complex operator*=(Complex &c2);
void display();
private:
    double real;
    double imag;
};
Complex Complex::operator*=(Complex &c1)
{Complex c;
    c.real=real*c1.real-imag*c1.imag;
    c.imag=real*c1.imag+imag*c1.real;
    
return c;}
void Complex::display()
{cout<<" "<<real<<"+"<<imag<<"i"<<endl;}
int main()
{Complex c1(2,3),c2=(4,5),c3;
c3=c1*=c2;
cout<<"c1*=";c1.display();
cout<<"c2*=";c2.display();
cout<<"c1*c2=";c3.display();
return 0;
}

Answer 1

#include <iostream>
using namespace std;
class Complex
{
public:
    int real;
    int image;
public:
    Complex(int r, int i)
    {
        real = r; image = i;
    }
    Complex(int r)
    {
        real = r; image = 0;
    }
    Complex()
    {
        real = 0; image = 0;
    }
 
    ~Complex()
    {
        //do nothing
    }
    Complex operator *= (const Complex Right) 
    {
        int a = real, b = image;
        real = a * Right.real - b * Right.image;
        image = b * Right.real + a * Right.image;
        return *this;
    }
 
    Complex operator *= (const int n) 
    {
        Complex t(n, 0);
        *this *= t;
        return *this;
    }
    friend void print(Complex comp);
 
};
 
 
void print(Complex comp)
{
    cout << comp.real;
    if (comp.image < 0)
        cout << comp.image << "i" << endl;
    else if (comp.image > 0)
        cout <<"+" << comp.image << "i" << endl;
}
 
int main()
{
    Complex c1(2, 3);
    Complex c2(2, 3);
    
    
    //显示C1
    cout<<"c=";
    print(c1);
 
    //与int类型相乘
    c1 *= 5;
    cout<<"c*=5,c=";
    print(c1);
 
    
    //与复数相乘
    cout<<"c*=4+5i,";
    Complex t(4, 5);
    c2 *= t;
    print(c2);
 
    return 0;
}