matrix数列不重复的代码需要帮助

Question

sample input:
295743861
431865927
876192543
387459216
612387495
549216738
763524189
928671354
154938672

output: Yes

sample input:
195743862
431865927
876192543
387459216
612387495
549216738
763524189
928671354
254938671

output: No

每次input九行数字，每行数字从1到9，顺序打乱，没有重复，这个输入的时候注意就可以了，不用考虑进程序，
然后关键点在这里，举个例子，第一行第二行第三行的前三位和第一列第二列第三列的前三位，正好3*3，这九个
数字从一到九不能有重复，一共有九组这样matrix，只要有一组里面发现有重复数字，最终output就是No，如果九组
都没有，那就是Yes
下面是我写的代码，能够正常运行出output，只是太繁琐，不简练，我有试过用函数套函数的方法，但没有成功，虽然
能够运行成功，但是这是失败的代码，不能这样繁琐
请求协助

```python
sample_input1=input("")
sample_input2=input("")
sample_input3=input("")
sample_input4=input("")
sample_input5=input("")
sample_input6=input("")
sample_input7=input("")
sample_input8=input("")
sample_input9=input("")

def counting(sample_input):
    for i in sample_input:
        if sample_input.count(i) != 1:
            check=False
            return check

new_list1=[]
for i in range(0,len(sample_input1)//3):
    new_list1.append(sample_input1[i])

new_list2=[]
for i in range(0,len(sample_input2)//3):
    new_list2.append(sample_input2[i])


new_list3=[]
for i in range(0,len(sample_input3)//3):
    new_list3.append(sample_input3[i])

lst=new_list1+new_list2+new_list3
new_string=""
row_column_string=new_string.join(lst)
group_check_1=counting(row_column_string)

new_list4=[]
for i in range(3,len(sample_input1)-3):
    new_list4.append(sample_input1[i])

new_list5=[]
for i in range(3,len(sample_input2)-3):
    new_list5.append(sample_input2[i])

new_list6=[]
for i in range(3,len(sample_input3)-3):
    new_list6.append(sample_input3[i])

lst1=new_list4+new_list5+new_list6
new_string1=""
row_column_string1=new_string1.join(lst1)
group_check_2=counting(row_column_string1)

new_list7=[]
for i in range(6,len(sample_input1)):
    new_list7.append(sample_input1[i])

new_list8=[]
for i in range(6,len(sample_input2)):
    new_list8.append(sample_input2[i])

new_list9=[]
for i in range(6,len(sample_input3)):
    new_list9.append(sample_input3[i])

lst2=new_list7+new_list8+new_list9
new_string2=""
row_column_string2=new_string2.join(lst2)
group_check_3=counting(row_column_string2)


new_list10=[]
for i in range(0,len(sample_input4)//3):
    new_list10.append(sample_input4[i])


new_list11=[]
for i in range(0,len(sample_input5)//3):
    new_list11.append(sample_input5[i])

new_list12=[]
for i in range(0,len(sample_input6)//3):
    new_list12.append(sample_input6[i])

lst3=new_list10+new_list11+new_list12
new_string3=""
row_column_string3=new_string3.join(lst3)
group_check_4=counting(row_column_string3)


new_list13=[]
for i in range(3,len(sample_input4)-3):
    new_list13.append(sample_input4[i])

new_list14=[]
for i in range(3,len(sample_input5)-3):
    new_list14.append(sample_input5[i])

new_list15=[]
for i in range(3,len(sample_input6)-3):
    new_list15.append(sample_input6[i])

lst4=new_list13+new_list14+new_list15
new_string4=""
row_column_string4=new_string4.join(lst4)
group_check_5=counting(row_column_string4)

new_list16=[]
for i in range(6,len(sample_input4)):
    new_list16.append(sample_input4[i])

new_list17=[]
for i in range(6,len(sample_input5)):
    new_list17.append(sample_input5[i])

new_list18=[]
for i in range(6,len(sample_input6)):
    new_list18.append(sample_input6[i])

lst5=new_list16+new_list17+new_list18
new_string5=""
row_column_string5=new_string5.join(lst5)
group_check_6=counting(row_column_string5)


new_list19=[]
for i in range(0,len(sample_input7)//3):
    new_list19.append(sample_input7[i])

new_list20=[]
for i in range(0,len(sample_input8)//3):
    new_list20.append(sample_input8[i])

new_list21=[]
for i in range(0,len(sample_input9)//3):
    new_list21.append(sample_input9[i])

lst6=new_list19+new_list20+new_list21
new_string6=""
row_column_string6=new_string6.join(lst6)
group_check_7=counting(row_column_string6)

new_list22=[]
for i in range(3,len(sample_input7)-3):
    new_list22.append(sample_input7[i])

new_list23=[]
for i in range(3,len(sample_input8)-3):
    new_list23.append(sample_input8[i])

new_list24=[]
for i in range(3,len(sample_input9)-3):
    new_list24.append(sample_input9[i])

lst7=new_list22+new_list23+new_list24
new_string7=""
row_column_string7=new_string6.join(lst7)
group_check_8=counting(row_column_string7)

new_list25=[]
for i in range(6,len(sample_input7)):
    new_list25.append(sample_input7[i])

new_list26=[]
for i in range(6,len(sample_input8)):
    new_list26.append(sample_input8[i])

new_list27=[]
for i in range(6,len(sample_input9)):
    new_list27.append(sample_input9[i])

lst8=new_list25+new_list26+new_list27
new_string8=""
row_column_string8=new_string6.join(lst8)
group_check_9=counting(row_column_string8)



counter=0
group_check=[]
group_check.append(group_check_1)
group_check.append(group_check_2)
group_check.append(group_check_3)
group_check.append(group_check_4)
group_check.append(group_check_5)
group_check.append(group_check_6)
group_check.append(group_check_7)
group_check.append(group_check_8)
group_check.append(group_check_9)
for i in range(0,len(group_check)):
    if group_check[i]==False:
        print("No")
        break
    else:
        counter+=1

if counter==9:
    print("Yes")

```

Answer 1

把每行的各位数字放到各个set集合中,判断各个set集合长度是不是9
你题目的解答代码如下：

def fun():
    sets = [set() for i in range(9)]
    setf = [[set() for i in range(3)] for i in range(3)]
    for i in range(9):
        s = input()
        if len(set(s))!=9: #一行数字有重复
            return "No"
        for j,v in enumerate(s):
            sets[j].add(v)
            setf[i//3][j//3].add(v)

    for d in sets:
        if len(set(d))!=9: #一列数字有重复
            return "No"
    for f in setf:
        for d in f:
            if len(set(d))!=9: #9宫格数字有重复
                return "No"
    return "Yes"

print(fun())

如有帮助，请点击我的回答下方的【采纳该答案】按钮帮忙采纳下，谢谢!