2018-02-02 15:49
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Laravel _如何将查询注入Auth :: user()

I'm making a blog with laravel. When I look into user authentication, I have a few issues here. I have 2 tables, one is users: id, name, ... the other is role: user_id, privilege .. I need to check whether a user is admin or not, I will need a function like isAdmin() or a $isAdmin attribute. This is my function placed in the app/providers/AuthServiceProvider.php:

private static $isAdmin;

public static function isAdmin() {
    if (isset(self::$isAdmin)) {
        return self::$isAdmin;
    $user_privilege = DB::table('role')
            ['privilege', '=', 'admin'],
            ['user_id', '=', Auth::user()->id],
    self::$isAdmin = isset($user_privilege->privilege);
    return self::$isAdmin;

This code works fine, but this will require two queries to the database to check the user's admin rights. So I wanted to find a way to inject a query into Auth :: user () so that only one query would retrieve all the stuff I wanted. I'm a beginner with laravel. Can you help me?

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我正在制作一个带有laravel的博客。 当我查看用户身份验证时,我在这里遇到了一些问题。 我有2个表,一个是用户:id,name,...另一个是role:user_id,privilege ..我需要检查用户是否是admin,我需要一个像 isAdmin()这样的函数 $ isAdmin 属性。 这是我的功能放在 app / providers / AuthServiceProvider.php 中:

  private static $ isAdmin; 
public static function isAdmin()  {
 if(isset(self :: $ isAdmin)){
 return self :: $ isAdmin; 
 $ user_privilege = DB :: table('role')
  - > select('privilege  ')
  - > where([
 ['user_id','=',Auth :: user() - > id],\  n])
  - > get()
  - > first(); 
 self :: $ isAdmin = isset($ user_privilege-> privilege); 
 return self :: $ isAdmin; 

此代码工作正常,但这需要对数据库进行两次查询以检查用户的管理员权限。 所以我想找到一种方法将查询注入Auth :: user(),这样只有一个查询可以检索我想要的所有东西。 我是laravel的初学者。 你能帮助我吗?

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2条回答 默认 最新

  • doushi3803 2018-02-02 15:59

    I assume that user can have only one role. You can create isAdmin() method in the User model:

    public function isAdmin()
        return auth()->user()->role->privilege === 'admin';

    Define the relationship if you didn't do that yet:

    public function role()
        return $this->hasOne(Role::class);

    Then use it with auth()->user()->isAdmin().

    If a user can have many roles:

    public function isAdmin()
        return auth()->user()->roles->contains('admin');

    And the relationship:

    public function roles()
        return $this->hasMany(Role::class);
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