求写一个opencv很简单的小代码

Question

求一个可以用OpenCV求线段距离的代码！可以有偿，用C++， 最好也可以用javaCV
我本来打算用霍夫变化求线段长度，奈何时间不够了下午就要出结果
这种白底黑线的简单的图片可以识别就可以，可以识别出线段长度，以及线段的端点坐标

Answer 1

简单写一个，里面内凹的角起始点差一个像素，我懒得处理，你自己要是觉得不行自己处理下

#include<iostream>
#include<opencv2/opencv.hpp>
using namespace std;
using namespace cv;
struct Line {
    Point A, B;
    double distance;
};
double getDistance(Point A,Point B) {
    return sqrt((A.x - B.x)* (A.x - B.x) + (A.y - B.y)*(A.y - B.y));
}
int main()
{
    string path = "./3/1.jpg";
    Mat img = imread(path);
    Mat gray,binary;
    cvtColor(img, gray, COLOR_BGR2GRAY);
    threshold(gray, binary, 180,255, THRESH_BINARY_INV);
    vector<vector<Point>> contours;
    findContours(binary, contours, RETR_EXTERNAL, CHAIN_APPROX_SIMPLE);
    vector<Line> Lines; //存放找到结果Lines
    for (int i = 0; i < contours.size(); ++i) {
        for (int j = 0; j < contours[i].size(); ++j) {
            int k = (j +1)%contours[i].size();
            Point A = contours[i][j];
            Point B = contours[i][k];
            double distance = getDistance(A, B);
            if (distance > 2) {
                Line temp_line;
                temp_line.A = A;
                temp_line.B = B;
                temp_line.distance = distance;
                Lines.push_back(temp_line);
    
            }
        }
    }
    //绘制每条线:
    Mat drawImg = img.clone();
    for (int i = 0; i < Lines.size(); ++i) {
        Scalar color(rand() % 255, rand() % 255, rand() % 255 );
        line(drawImg, Lines[i].A, Lines[i].B, color, 1, 8);
    }
    imshow("src", img);
    imshow("res", drawImg);
    waitKey();
    return 0;
}