两段不同的代码,为什么args和kwargs的output格式有很大区别
```python
def combiner(a, b, *args, **kwargs):
super_combiner(args, kwargs)
def super_combiner(*args, **kwargs):
print('my_args:', args)
print('my_kwargs', kwargs)
combiner(10, '20', 40, 60, 30, argument1=50, argument2='66')
"""
output:
my_args: ((40, 60, 30), {'argument1': 50, 'argument2': '66'})
my_kwargs {}
"""
def test2(x,*args,**kwargs):
print("x: ", x)
print("args:",args)
print("kargs:",kwargs)
return
test2(1,2,a=1, b=2, c=3)
"""
output:
x: 1
args: (2,)
kargs: {'a': 1, 'b': 2, 'c': 3}
"""
```