dongqiang4986 2015-12-07 15:08
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PHP数组到对象

Given the following array:

$array = array(
    'item_1' => array(
            'item_1_1' => array(
                    'item_1_1_1' => 'Hello',
            ),
            'item_1_2' => 'World',
    ),
    'item_2' => array(),
);

How can I convert that into an Object?

Option 1
$obj = (object) $array;

Or

Option 2
$object = json_decode(json_encode($array), FALSE);

Or something else?

I would like to know the difference in the output between the 2 option and understand the best practice for creating this conversion.

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  • dongyinglan8707 2015-12-07 15:12
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    Well you are answering somehow your own question, but if you want to have an object with the attributes like your array you have to cast it, this way an array will remain an array

    $obj = (object) $array;
    

    OUTPUT:

    object(stdClass)#1 (2) {
      ["item_1"]=>
      array(2) {
        ["item_1_1"]=>
        array(1) {
          ["item_1_1_1"]=>
          string(5) "Hello"
        }
        ["item_1_2"]=>
        string(5) "World"
      }
      ["item_2"]=>
      array(0) {
      }
    }
    

    if you are using the json_decode version it will convert arrays to objects too:

    object(stdClass)#2 (2) {
      ["item_1"]=>
      object(stdClass)#3 (2) {
        ["item_1_1"]=>
        object(stdClass)#4 (1) {
          ["item_1_1_1"]=>
          string(5) "Hello"
        }
        ["item_1_2"]=>
        string(5) "World"
      }
      ["item_2"]=>
      array(0) {
      }
    }
    

    NOTE: just the empty array will be an array here.

    To Answer your question: The best practice depends on what YOU need.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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