关于#c##的问题：请求为post ，参数为body中raw

Question

要求使用nodejs或C#写一个请求参数为如下格式的接口。

请求为post ，参数为body中raw，只要能拿到三个值即可。如下为参数：

{
    "data": "{\"LightweightName\":\"SS\",\"status\":\"0\",\"Msg\":\"\"}"
}

大概达到的效果

Answer 1

使用System.Text.Json或者Newtonsoft.Json将POST请求中的data反序列化成对应的对象即可，.NET 6(C#)的实现示例如下：

using Microsoft.AspNetCore.Mvc;
using Newtonsoft.Json;

namespace RequestRawDemo.Controllers
{
    [ApiController]
    [Route("[controller]/[action]")]
    public class UploaderController : ControllerBase
    {

        [HttpPost]
        public LightWeight? Upload([FromBody] LightWeightRequest request)
        {
            return request.LightWeight;
        }
    }

    public class LightWeightRequest
    {
        public string? Data { get; set; }
        public LightWeight? LightWeight => Data != null ? JsonConvert.DeserializeObject<LightWeight>(Data) : new LightWeight();
    }
    public class LightWeight
    {
        public string? LightweightName { get; set; }
        public string? Status { get; set; }
        public string? Msg { get; set; }
    }
}

运行效果如下：