Python嵌套列表，怎么转字符串？

Question

[('abc', 'v', '12345'), ('abc', 'v', '67'), ('abc', 'c', '12345'), ('abc', 'c', '67'), ('abc', 'k', '12345'), ('abc', 'k', '67'), ('def', 'v', '12345'), ('def', 'v', '67'), ('def', 'c', '12345'), ('def', 'c', '67'), ('def', 'k', '12345'), ('def', 'k', '67')] [程序已完成]

竖排
变成普通文字

Answer 1

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lie = [('abc', 'v', '12345'), ('abc', 'v', '67'), ('abc', 'c', '12345'), ('abc', 'c', '67'), ('abc', 'k', '12345'),
       ('abc', 'k', '67'), ('def', 'v', '12345'), ('def', 'v', '67'), ('def', 'c', '12345'), ('def', 'c', '67'),
       ('def', 'k', '12345'), ('def', 'k', '67')]
list=[]
for i in range(0,len(lie)):
    list.append(','.join(lie[i]))

result='\n'.join(list)
print(result)