变量不能按预期工作，并且正在创建一个数组

Question

I'm using this line of code:

$var{++$counter} = $results['row'];

I've set this up with a goal of creating these variables:

$var1 = row 1
$var2 = row 2
$var3 = row 3

Why is it created an array for $var ? Instead of just defining three variables?

Answer 1

Simply because {} can also be used to access arrays as you can read from the manual:

Note: Both square brackets and curly braces can be used interchangeably for accessing array elements (e.g. $array[42] and $array{42} will both do the same thing in the example above).

Means the following 2 lines are the same:

$var{++$counter}
$var[++$counter] 

What you want is variable variables, which would be this:

${"var" . ++$counter} = $results['row'];