定义为int x执行不了，都定义为dou类型才能正确运行

Question

#include<stdio.h>;
#include<math.h>;

int main()
{
/int x;/
double x,y;
printf("输入x\n");
scanf_s("%lf", &x);
if (x == 0) {
y = 1;
}
else {
y =1/x;
}
printf("y=f(%f)=%.2lf\n",x, y);
return 0;
}

Answer 1

%lf,接收，输出只能是小数呀，int要用%d