匹配数组值对（PHP）

Question

I've been battling with this for HOURS and I am completely stuck.

I'm randomly generating numbers and finding their prime factors. For example...

Prime Factors of 420: 2, 2, 3, 5, 7
Prime Factors of 690: 2, 3, 5, 23

I want to highlight the matching pairs and "uncommon" factors separately as I list them out. So, in this case I would want something like...

Prime Factors of 420: 2, 2, 3, 5, 7
Prime Factors of 690: 2, 3, 5, 23

Then the other 2 and the 7 from 420, and the 23 from 690 would be highlighted in red (for example).

I already have the lists of prime factors in arrays ($factor_list_1_old and $factor_list_2_old respectively). I also have the list of common factors in an array ($commons) and a list of the uncommon factors in an array ($uncommons).

I've tried many ways of doing this and nothing seems to work for all scenarios. I can get this scenario to work, but then it fails for something like 420 and 780.

Any ideas?

Answer 1

My function

$array1 = array(2, 2, 3, 5, 7);
$array2 = array(2, 3, 5, 23);

function highlightFactors($factors, $other_factors)
    {
    $result = array();
    foreach ($factors as $factor)
        {
        if (($found_key = array_search($factor, $other_factors)) === false)
            {
            $result[] = array($factor, 'normal');
            }
        else
            {
            $result[] = array($factor, 'bold');
            unset($other_factors[$found_key]);
            }
        }
    return $result;
    }

echo json_encode(highlightFactors($array1, $array2));
// [[2,"bold"],[2,"normal"],[3,"bold"],[5,"bold"],[7,"normal"]]
echo json_encode(highlightFactors($array2, $array1));
// [[2,"bold"],[3,"bold"],[5,"bold"],[23,"normal"]]