PHP：可以防止功能回显到屏幕？

Question

Ok I know the title is a bit confusing as I can't think of a good way to explain it. There is this function which I don't have access to and it looks something like this:

<?php function myFunction() {
?> '<img src="one.jpg" />';
<?php } ?>

Ok so everytime that function is called, it echo's the img tag. But what if I want to manipulate the img tag before it echos to the screen? Is it possible?

I want to assign it to a variable first, manipulate it and then I will echo it out. Something like this:

$image_src = myFunction();
$image_src = preg_replace('/s.*"/', $image_src);
echo $image_src;

Something like this possible?

Answer 1

Use output buffering:

ob_start();
myFunction();
$output = ob_get_clean();

after that, $output will contain the html that was echoed inside the function.