Qt和c++里对派生类继承里编译的错误，如何解决？

Question

注意：qt和c++编译器不一样

这段代码能来一个说一下吗？

void setNum(int derivednum1, int derivednum2, int derivednum3)
     {
           derivednum1 = derivednum1;
           derivednum2 = derivednum2;
           derivednum3 = derivednum3;
     }

全部代码：

#include<iostream>
using namespace std;
class Base
{
public:
    int basenum1;
private:
    int basenum2;
protected:
    int basenum3;
public:
    //在类的内部，通过类成员方法或友元函数，各成员均可访问
    void setNum(int a, int b, int c)
    {
        basenum1 = a;
        basenum2 = b;
        basenum3 = c;
    }
    friend void print(Base& b);//声明友元函数
    void getnum()
    {
        cout << basenum1 << basenum2 << basenum3 << endl;
    }
};
void print(Base& b) {//定义友元函数，非类成员函数，可实现类外访问
    cout << b.basenum1 << " " << b.basenum2 << " " << b.basenum3 << endl;
}
class Derived : public Base {
public:
    int derivednum1;
private:
    int derivednum2;
protected:
    int derivednum3;
public:
    //在派生类内部只能访问基类的public成员和protected成员，不能访问基类的private成员
    //不看派生类的继承方式
    void setNum(int derivednum1, int derivednum2, int derivednum3)
    {
        derivednum1 = derivednum1;
        derivednum2 = derivednum2;
        derivednum3 = derivednum3;
    }
    friend void print(Derived& d)
    {
        d.basenum1 = 10;
        //d.basenum2 = 17;//基类的私有成员，在派生类中不可访问
        d.basenum3 = 15;
        cout << d.derivednum1 << " " << d.derivednum2 << " " << d.derivednum3 << endl;
    }
};
class Derived1 : private Base {
public:
    void print()
    {
        //basenum2 = 10; //基类的私有成员，在派生类中不可访问
        cout << basenum1 << " " << basenum3 << endl; //基类的公有成员和保护成员，在派生类中 //可访问
    }
};
class Derived2 : protected Base
{
public:
    void print()
    {
        //basenum2 = 10; //基类的私有成员，在派生类中不可访问
        cout << basenum1 << " " << basenum3 << endl; //基类的公有成员和保护成员，在派生类中 //可访问
    }
};
int main()
{
    Base b;
    b.basenum1 = 10;
    //b.basenum2 = 10;  //在类的外部不可访问，private
    //b.basenum3 = 15;  //在类的外部不可访问，protected
    b.setNum(14, 16, 17);
    print(b);
    b.getnum();
    //在派生类的外部访问基类中的成员时，会根据继承方式影响基类成员的访问级别
    //1.public 继承
    Derived d;
    d.basenum1 = 10; //public - public，可被访问
    //d.basenum2 = 15; //private -- private，不可被访问
    //d.basenum3 = 10; //protected -- protected，不可被访问
    print(d);
    //2.private 继承
    Derived1 d1;
    //d1.basenum1 = 15; //public -- private，不可被访问
    //d1.basenum2 = 10; //private -- private，不可被访问
    //d1.basenum3 = 20; //protected -- private，不可被访问
    d1.print();
    //3.protected 继承
    Derived2 d2;
    //d2.basenum1 = 10; //public -- protected，不可被访问
    //d2.basenum2 = 16; //private -- private，不可被访问
    //d2.basenum3 = 9; //protected -- protected，不可被访问
    d2.print();
    return 0;
}

这是vs输出：

这是qt输出：

能讲一下吗

Answer 1

这个类函数肯定有问题啊，代码做了无用功，改为：

void setNum(int derivednum1, int derivednum2, int derivednum3)
    {
        this->derivednum1 = derivednum1;
        this->derivednum2 = derivednum2;
        this->derivednum3 = derivednum3;
    }