Vector类实现，动态内存下标越界

Question

Vector类实现，动态内存下标越界
这是另一个博主的代码，我的疑惑是，如果输入的n超过初始设置的100，add()函数里不会造成下标越界吗

template <class T>
class Vector
{
private:
    int pos;
    int size = 100;
    T* data;
public:
    Vector() {
        pos = 0;
        data = new T[size];
    }
    int add(T m) {
        data[pos]=m;
        pos++;
        return pos-1;
    }
    int get_size() { return pos; }
    void remove(int m) {
        for (int i = m; i < pos-1; i++) {
            data[i] = data[i + 1];
        }
        pos--;
    }
    const T& operator[](int index)const
    {
        return data[index];
    }
};
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版权声明：本文为CSDN博主「我不想起名字呀」的原创文章，遵循CC 4.0 BY-SA版权协议，转载请附上原文出处链接及本声明。
原文链接：https://blog.csdn.net/qq_47867028/article/details/117336559

int main()
{
    Vector<int> vint;
    int n, m;
    cin >> n >> m;
    for (int i = 0; i < n; i++) {
        //    add() can inflate the vector automatically
        vint.add(i);
    }
    //    get_size() returns the number of elements stored in the vector
    cout << vint.get_size() << endl;
    cout << vint[m] << endl;
    //    remove() removes the element at the index which begins from zero
    vint.remove(m);
    cout << vint.add(-1) << endl;
    cout << vint[m] << endl;
    Vector<int> vv = vint;
    cout << vv[vv.get_size() - 1] << endl;
    vv.add(m);
    cout << "vint size:" << vint.get_size() << endl;
    cout << "vv size:" << vv.get_size() << endl;
    cout << vint.get_size() << endl;
}

Answer 1

size在构造函数里初始化
size=10放在构造函数里。