display.html :
<div id="display_result" style="display: none"><table class="table">
<p style="float: right;" >Select All<input type="checkbox" class="allcb" data-child="chk" checked/> </p>
<thead>
<tr>
<th>Die No</th>
<th> Status </th>
<th> Location </th>
<th>Select</th>
</tr>
</thead>
<tbody>
</table>
<div id ="issue_button">
<input type="submit" id="submit" class="btn btn-success " value="Recieve" style="width: 150px;"></div>
</div>
Ajax:
var data = JSON.stringify($("#form").serializeArray());
// alert(data);
$.ajax({ // Send the credential values to another checker.php using Ajax in POST menthod
type: 'POST',
data: {
list: data
},
url: 'die_recieving_process.php',
success: function(data) ){
$('#display_result').html(data);
}
});
die_recieving_process.php
while($fetch = mysql_fetch_array($query))
{
if($fetch[1] == "Table Rack" )
{
echo '<tr class="success"><td>'.$fetch[0].'</td><td>'.$fetch[1].'</td><td>'.$fetch[3] . '</td> <td><input type=checkbox class="chk" id=check_box value= '.$fetch[2].' name= check_list[] </td> </tr>';
}
else
{
echo '<tr class="warning"><td>'.$fetch[0].'</td><td>'.$fetch[1].'</td><td>'.$fetch[3] . '</td> <td><input type=checkbox class="chk" id=check_box value= '.$fetch[2].' name= check_list[] checked </td> </tr>';
}
}
Hi friends in display.html I have to display the result processed in die_recieving_process.php . In ajax i've sent all the value to die_recieving_process.php and after fetching the result i've to display the result in display.html
