dongmei3869 2013-08-15 13:35
浏览 66
已采纳

CakePHP和用户登录功能

Here is a simple CakePHP login function (example taken from the CakePHP cookbook):

public function login() {
    if ($this->request->is('post')) {
        if ($this->Auth->login()) {
            return $this->redirect($this->Auth->redirectUrl());
        } else {
            $message = 'Username or password is incorrect';
            $this->Session->setFlash(__($message), 'default', array(), 'auth');
        }
    }
}

During testing of this login function I found out that:

if ($this->Auth->login()) {
    // ...
}

It lets a user to login even if authorization was done earlier. For example, if I logged in as User1 and without a call to logout function I'm trying to log in as User2 - I will get the next error:

Notice (8): Undefined index: User [APP/Controller/UsersController.php, line 83]

In this case I can hide a login form from the user. Is it a correct way?

Update: what can you say about the next code snippet:

public function login() {
    if ($this->request->is('post')) {
        if ($this->Auth->loggedIn()) {
            $this->Auth->logout();
        }
        if ($this->Auth->login()) {
            return $this->redirect($this->Auth->redirectUrl());
        } else {
            $message = 'Invalid login or password';
            $this->Session->setFlash(__($message), 'default', array(), 'auth');
        }
    }
}
  • 写回答

2条回答 默认 最新

  • dongzhimeng2464 2013-08-30 19:28
    关注

    The tutorial Simple Acl controlled Application - part 2 in the cookbook suggests that you read out the data with SessionComponent.

    You can also use the AuthComponent to check whether a user is already logged in or not. Use $this->Auth->user() in your controller. You can also pass a key to the first parameter to get a specific column of your users table or skip it to get all of the user's information. It returns Null if the user is not logged in or the key does not exist.

    Your login method could look like the following one (additions marked with a plus + and SessionComponent is used):

    public function login() {
    +   if ($this->Session->read('Auth.User')) {
    +       $this->Session->setFlash('You are logged in!');
    +       return $this->redirect($this->Auth->redirectUrl());
    +   }
        if ($this->request->is('post')) {
            if ($this->Auth->login()) {
                return $this->redirect($this->Auth->redirectUrl());
            } else {
                $message = 'Username or password is incorrect';
                $this->Session->setFlash(__($message), 'default', array(), 'auth');
            }
        }
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥15 改算法,照着压缩包里边,参考其他代码封装的格式 写到main函数里
  • ¥15 用windows做服务的同志有吗
  • ¥60 求一个简单的网页(标签-安全|关键词-上传)
  • ¥35 lstm时间序列共享单车预测,loss值优化,参数优化算法
  • ¥15 Python中的request,如何使用ssr节点,通过代理requests网页。本人在泰国,需要用大陆ip才能玩网页游戏,合法合规。
  • ¥100 为什么这个恒流源电路不能恒流?
  • ¥15 有偿求跨组件数据流路径图
  • ¥15 写一个方法checkPerson,入参实体类Person,出参布尔值
  • ¥15 我想咨询一下路面纹理三维点云数据处理的一些问题,上传的坐标文件里是怎么对无序点进行编号的,以及xy坐标在处理的时候是进行整体模型分片处理的吗
  • ¥15 一直显示正在等待HID—ISP