2、求
当n=100,a=0.5,x=-0.5时的值(精值到4位小数)
#include <iostream>
using namespace std;
int main()
{
double k = 1;
double n = 0;
double j = 1;
double a = 0.5;
double x = -0.5;
double sum = 0;
for (n = 1;n <=100;n++)
{
j *= ((a * x) / k);
sum = sum + j;
a = a - 1;
x = x * x;
k *= n;
}
cout << sum + 1;
}
算上面的,我发现算到第三次的结果跟算到100次的结果是一样的,是不是数据类型不对