java按一定序列输出立方体相关信息

Question

(请提供完整补充代码)java定义一个立方体类，定义10个立方体，立方体用数组存储，并分别按照立方体的体积降序排列，体积相同时按照3边和升序排列（长+宽+高），3边和相同时，再按照长降序排列。
我的代码如下，但是只会按体积降序排列，不能同时满足题目中其他条件。

public class Cube {
    float chang;
    float kuan;
    float gao;
    float tj;
    public Cube() {
        super();
        // TODO Auto-generated constructor stub
    }

    public Cube(float chang, float kuan, float gao) {
        super();
        this.chang = chang;
        this.kuan = kuan;
        this.gao = gao;
        this.tj = chang*kuan*gao;
    }

    public float getChang() {
        return chang;
    }

    public void setChang(float chang) {
        this.chang = chang;
    }

    public float getKuan() {
        return kuan;
    }

    public void setKuan(float kuan) {
        this.kuan = kuan;
    }

    public float getGao() {
        return gao;
    }

    public void setGao(float gao) {
        this.gao = gao;
    }

    public float getTj() {
        return chang*kuan*gao;
    }

    @Override
    public String toString() {
        return "Cube [chang=" + chang + ", kuan=" + kuan + ", gao=" + gao + ", tj=" + tj + "]";
    }

    
}
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.Comparator;

public class pro2 {
    public static void main(String[] args) {
        Cube[] cus1=new Cube[10];
        float chang,kuan,gao;
        for (int i = 0; i < cus1.length; i++) {
            chang =(float)(Math.random()*5+5);
            kuan=(float)(Math.random()*1+3);
            gao=(float)(Math.random()*5+10);
            cus1[i]=new Cube(chang,kuan,gao);
        }
    
        Arrays.sort(cus1,new Comparator<Cube>() {

            @Override
            public int compare(Cube o1, Cube o2) {
                if(o1.getTj()>o2.getTj())
                    return -1;
            else if(o1.getTj()==o2.getTj())
     return 0;
      
        else
     return 1;
       
   }
   
  });
  for (int i = 0; i < cus1.length; i++) {
   System.out.println(cus1[i].toString());
  }
}}

Answer 1

 else if(o1.getTj()==o2.getTj())

在体积相同的if内，进一步判断长宽高大小比较。