douan0729 2012-07-13 08:08
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如何为每组用户实现序列号数据库?

It's easy to create a database table for storing sequence numbers ; but this design is suited for the event when the sequence is shared for all users. What I want is to create sequence for each group of users : this group can grow at any time because it's a database table , that is the administrator can create a group at any time and users are assigned to a specific group. So how to implement the sequence generation according to a group ?

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  • douchuituo3032 2012-07-13 08:12
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    if you are using myisam

    http://dev.mysql.com/doc/refman/5.0/en/example-auto-increment.html

    Below extracted from above links.

    For MyISAM and BDB tables you can specify AUTO_INCREMENT on a secondary column in a multiple-column index. In this case, the generated value for the AUTO_INCREMENT column is calculated as MAX(auto_increment_column) + 1 WHERE prefix=given-prefix. This is useful when you want to put data into ordered groups.

    CREATE TABLE animals (
        grp ENUM('fish','mammal','bird') NOT NULL,
        id MEDIUMINT NOT NULL AUTO_INCREMENT,
        name CHAR(30) NOT NULL,
        PRIMARY KEY (grp,id)
    ) ENGINE=MyISAM;
    
    INSERT INTO animals (grp,name) VALUES
        ('mammal','dog'),('mammal','cat'),
        ('bird','penguin'),('fish','lax'),('mammal','whale'),
        ('bird','ostrich');
    
    SELECT * FROM animals ORDER BY grp,id;
    Which returns:
    
    +--------+----+---------+
    | grp    | id | name    |
    +--------+----+---------+
    | fish   |  1 | lax     |
    | mammal |  1 | dog     |
    | mammal |  2 | cat     |
    | mammal |  3 | whale   |
    | bird   |  1 | penguin |
    | bird   |  2 | ostrich |
    +--------+----+---------+
    

    For your case:

    CREATE TABLE mytable (
       user_id MEDIUMINT NOT NULL AUTO_INCREMENT,
        group_id MEDIUMINT NOT NULL,   
         user_name CHAR(30) NOT NULL,
        PRIMARY KEY (group_id,user_id)
         ) ENGINE=MyISAM;
    
    
    INSERT INTO mytable (group_id, user_name) VALUES
         (1,'alex'),(1,'jenny'),(2,'baz'),(1,'tim'),(2,'danny'),(3,'joe');
    
    
    SELECT * FROM mytable ORDER BY group_id,user_id;
    

    Returns:

    user_id group_id    user_name
    1            1          alex
    2            1          jenny
    3            1          tim
    1            2          baz
    2            2          danny
    1            3          joe
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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