dongsha2792 2013-04-19 22:18
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如何从MYSQL表中显示3个随机值

How would I go about displaying 3 random values each time a page is loaded? At the minute I have it displaying one at a time using the following code:

<?php
$sSQLQuery = "SELECT careername FROM careers ORDER BY RAND() LIMIT 1";  
$aResult = mysql_query($sSQLQuery);  
$aRow = mysql_fetch_array($aResult, MYSQL_ASSOC);  
$sQuoteOfTheDay = $aRow['careername']; 
echo $sQuoteOfTheDay;   
?>

I have tried doing LIMIT 5 but that had no effect on the result. Thanks

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4条回答 默认 最新

  • duandu8202 2013-04-19 22:20
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    You'll have to call mysql_fetch_assoc() again for every single record your are fetching.

    So, use LIMIT 3 and then simply loop through the result set. Like this:

    $sSQLQuery = "SELECT careername FROM careers ORDER BY RAND() LIMIT 3";  
    $aResult = mysql_query($sSQLQuery);  
    while($aRow = mysql_fetch_array($aResult, MYSQL_ASSOC)) {
        $sQuoteOfTheDay = $aRow['careername']; 
        echo $sQuoteOfTheDay; 
    }
    

    Refer to the manual page of mysql_fetch_assoc(). You'll find more examples there.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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