PHP循环显示每天的唯一消息

Question

I have 24 days which have unique messages each day. How could i write the following IF statements in some sort of loop to make it more efficient: -

<?

if ($day == '1') {

  $offerTxt = $day1Txt;

} else if ($day == '2') {

  $offerTxt = $day2Txt;

} else if ($day == '3') {

  $offerTxt = $day3Txt;

} else if ($day == '4') {

  $offerTxt = $day4Txt;

} else if ($day == '5') {

  $offerTxt = $day5Txt;

} else if ($day == '6') {

  $offerTxt = $day6Txt;

} 


?>

Answer 1

You can do this inline like this:

$offerTxt = ${'day'.$day.'Txt'};

You should probably check whether the day is in a certain set, so your code would come out looking similar to this:

$daysUsed = array(1,2,3,4,5,6);
$offerTxt = '';
if(in_array((int)$day, $daysUsed)) {
    $offerTxt = ${'day'.$day.'Txt'};
}