array_a是否包含array_b的所有元素

Question

If this is $array_b

$array_b = array('red', 'green', 'blue'); 

What's an efficient way to compare it to $array_a and get a boolean as to whether $array_a contains all elements of the above $array_b.

This is the output I'm trying to get to

//false, because it's missing the red from `$array_b`
$array_a = array('green', 'blue'); 

//true, because it contains all 3 from `$array_b`
$array_a = array('red', 'green', 'blue');     

//true, because it contains all 3 from `$array_b`
//even though there's an extra orange and cyan
$array_a = array('red', 'green', 'blue', 'orange', 'cyan'); 

What's a good way to do this without nasty nested loops that are hard to keep track of?

Answer 1

if (count(array_intersect($array_a, $array_b)) == count($array_b)) {
    ...
}

or as function

function function_name($array_a, $array_b) {
    return count(array_intersect($array_a, $array_b)) == count($array_b);
}