返回函数不工作，但echo在PHP中工作

Question

i have the following function when i try and return the vaule its only shows 1 folder but when i echo the function it show the correct informaion.

PHP Code:

$FolderList = "";

function ListFolder($path) {
    $path = str_replace("//","/",$path);

    //using the opendir function
    $dir_handle = @opendir($path) or die("Unable to open $path");

    //Leave only the lastest folder name
    $dirname = end(explode("/", $path));

    //display the target folder.
    $FolderList .= ('<option value="">'.$path.'</option>');

    while(false !== ($file = readdir($dir_handle))) {
        if($file!="." && $file!="..") {
            if(is_dir($path."/".$file)) {
                //Display a list of sub folders.
                ListFolder($path."/".$file);
            }
        }
    }

    //closing the directory
    closedir($dir_handle);

    return $FolderList; //ERROR: Only Shows 1 Folder
    echo $FolderList; //WORKS: Show All The Folders Correctly
}

Thanks

Answer 1

Give this a shot:

function ListFolder($path)
{
    $path = str_replace("//","/",$path);

    //using the opendir function
    $dir_handle = @opendir($path) or die("Unable to open $path");

    //Leave only the lastest folder name
    $dirname = end(explode("/", $path));
    //display the target folder.
    $FolderList = ('<option value="">'.$path.'</option>');
    while (false !== ($file = readdir($dir_handle)))
    {
        if($file!="." && $file!="..")
        {
            if (is_dir($path."/".$file))
            {
                //Display a list of sub folders.
                $FolderList .= ListFolder($path."/".$file);
            }
        }
    }


    //closing the directory
    closedir($dir_handle);

    return $FolderList;
}

echo ListFolder('/path/to/folder/');

I simply changed the $FolderList to be assigned to the return value of the ListFolder function.