具有依赖注入的同一类的Mock方法 - PHP

Question

i was wondering on how i can mock a method on the same class that this class have a dependency itself.

Let's say an example:

Class SomeClassA {

  protected $dependency;

  function __construct(Dependency $dependency) {

     $this->dependency = $dependency;

  }


  public function methodToTest() {

         if ( !is_null( $this->methodCalled() ) )

            return $this->methodCalled();

         else

            return "it\'s not ok!"

         // need to test this method mocking the methodCalled()

  }


  public function methodCalled($message) {

        return $message;

  }


}

if this class did not have the dependency i could do something like so:

public function test_methodToTest() {

    $this->getMock('SomeClassA',['methodCalled'])
         ->with('message')
         ->expects($this->once())
         ->will($this->returnValue('message'));

   $someClassA = new SomeClassA();

   $this->assertEquals('message',$someClassA->methodToTest('message'));


}

Edit:

Let's say this example to improve the meaning of my question i just changed a little bit the previous example:

Class SomeClassA {

  protected $dependency;

  function __construct(Dependency $dependency) {

     $this->dependency = $dependency;

  }


  public function methodToTest() {

         if ( $this->methodCalled() ) // i was wondering how mock this method

            return $this->dependency->someDependencyMethod(); // not this

         else

            return "it\'s not ok!"



  }


  public function methodCalled() {

        return true;

  }


}

I just didn't understand how I can mock the method $this->methodClass(). I found hard it because the class SomeClassA have a dependency. And i'm testing a method of that class.

Answer 1

You can do as follows:

class SomeClassATest {
    public function testMethodToTest() {
        $someClassA = $this->getMockBuilder('SomeClassA')
            ->setMethods(array('methodCalled'))
            ->getMock();
        $someClassA->expects($this->once())
            ->method('methodCalled')
            ->will($this->returnValue('your mocked value here'));
        $actual = $someClassA->methodToTest();
        $this->assertEquals('your expectation here', $actual);
    }
}

This will only work if methodCalled is either public or protected, since you can only mock public and protected methods. The way it works up there is you are testing $someClassA, a mock instance of SomeClassA, where only methodCalled is replaced with your test behavior, and everything else stays the same.