1375 ：单词处理【C/C++/Java/Python】

Question

题目描述
给定一个由英文字符、数字、空格和英文标点符号组成的字符串，长度不超过2000，请将其切分为单词，要求去掉所有的非英文字母，每行输出一个单词。
例如有文本：Python was created in 1990 by Guido van Rossum at Stichting Mathematisch Centrum (CWI, see http://www.cwi.nl) in the Netherlands.
处理完成之后得到以下单词：

Python
was
created
in
by
Guido
van
Rossum
at
Stichting
Mathematisch
Centrum
CWI
see
http
www
cwi
nl
in
the
Netherlands
问题：在编程训练系统中测评完成率只有10%，我在VS上运行时得出的结果是正常的，想知道是哪里出的问题。********
我的代码：

#include"stdio.h"
int hanshu(char ch)
{
    if ((ch >= 'a' && ch <= 'z') || (ch >= 'A' && ch <= 'Z'))
    {
        return 1;
    }
    else
    {
        return 0;
    }
}
int main()
{
    char ch[2000];
    fgets(ch, 2000, stdin);
    int i = 0;
    int flag = 0;
    int f = 1;
    while (ch[i] != '\n')
    {
         if (hanshu(ch[i])==1)
        {
            printf("%c", ch[i]);
            f = 0;
          
        }
        else if(f==0&&hanshu(ch[i])==0)
        {
             flag = 1;
            
        }
         if (flag == 1 && f == 0)
         {
             if (ch[i + 1] != '\n')
             {
                 printf("\n");
                 flag = 0;
                 f = 1;
             }
         }
         i++;
    }
    return 0;
}

Answer 1

正确答案

#include <stdio.h>
#include <stdlib.h>

/* run this program using the console pauser or add your own getch, system("pause") or input loop */

int main(int argc, char *argv[]) {
    int h=0,i;
    char ch[2000];
    gets(ch);
    for(i=0;ch[i]!='\0';i++){
        if((ch[i]>='a'&&ch[i]<='z')||(ch[i]>='A'&&ch[i]<='Z'))
        {
            if(h!=0)
            {
                printf("\n");
                h=0;
            }
            printf("%c",ch[i]); 
        }
        else
        {
            h++;
        }
    }
    

    
    return 0;
}