正则表达式PHP只获得第一场比赛

Question

I have an string which looks like:

aaaaaaaa'bbbbbbbb?'cccccccccccc'ddddddddd'

I would like to get all the matches separate by ' but not the ones escaped with ?'

I managed to do it by using this expression:

(.*?)[^\\?]'

And I tested it on regexpal and seems to work properly.

When trying to apply it to my PHP code by using preg_match I only get the first match.

This is my code:

preg_match ("/(.*?)[^\\?]'/i", $content, $matches);
print_r($matches);

And the result is:

Array
(
    [0] => aaaaaaaaaaaaaaaa'
    [1] => aaaaaaaaaaaaaaa
)

I'm expecting to get bbbbbbbb?'cccccccccccc' and ddddddddd' as well. What am I doing wrong? Thanks.

Answer 1

You can use this negative lookbehind regex in preg_match_all:

$s = "aaaaaaaa'bbbbbbbb?'cccccccccccc'ddddddddd'";
if (preg_match_all("/(.*?)(?<!\?)'/", $s , $m ))
    print_r($m[1]);

OR using preg_split:

$arr = preg_split("/(?<!\?)'/", $s, -1, PREG_SPLIT_NO_EMPTY);

OUTPUT

Array
(
    [0] => aaaaaaaa
    [1] => bbbbbbbb?'cccccccccccc
    [2] => ddddddddd
)