关于“扫雷游戏”的问题

Question

#include<stdio.h>
void initBoard(char arr[102][102], int N, int M)
{
    for (int i = 0; i < 102; i++)
    {
        for (int j = 0; j < 102; j++)
        {
            arr[i][j] = '^';
        }
    }
    for (int i = 1; i <= N; i++)
    {
        for (int j = 1; j <= M; j++)
        {
            scanf_s("%c", &arr[i][j]);
        }
        getchar();
    }
}
int judge(char mine[102][102], int x, int y)
{
    if (mine[x][y] = '*')
        return 1;
    else
        return 0;
}
int minecount(char mine[102][102], int x, int y)
{
    int sum = 0;
    if (judge(mine,x - 1, y))
        sum++;
    if (judge(mine, x + 1, y))
        sum++;
    if (judge(mine, x - 1, y - 1))
        sum++;
    if (judge(mine, x + 1, y + 1))
        sum++;
    if (judge(mine, x - 1, y + 1))
        sum++;
    if (judge(mine, x + 1, y - 1))
        sum++;
    if (judge(mine, x, y - 1))
        sum++;
    if (judge(mine, x, y + 1))
        sum++;
        return sum;
}
void findMine(char arr[102][102], int N, int M)
{
    for (int i = 1; i <= N; i++)
    {
        for (int j = 1; j <= M; j++)
        {
            if (arr[i][j] == '*')
            {
                printf("%c", arr[i][j]);
            }
            else
            {
                printf("%d", minecount(arr, i, j));
            }
        }
        printf("\n");
    }
}
int main()
{
    int count = 1;
    int N = 0;
    int M = 0;
    char arr[102][102] = { 0 };
    while (scanf("%d %d\n", &N, &M) != EOF)
    {
        //         getchar();
        if (M == N && N == 0)
        {
            return 0;
        }
        initBoard(arr, N, M);
        printf("Field #%d:\n", count);
        findMine(arr, N, M);
        printf("\n");
        count++;
    }
    return 0;
}

扫雷数都是8，怎么解决？应该是27行的函数有问题，如何修改？

Answer 1

scanf_s("%c", &arr[i][j]);
改成
scanf_s("%c", &arr[i][j],1);
====
if (mine[x][y] = '*')
改为
if (mine[x][y] == '*')