有没有更短的判断井字棋胜利的代码（Python，如何解决？

Question

如标题所示，我使用的是把所有可能性都列出来判断，但希望可以得到简化！非常感谢，下面是代码：

the_board = {'top-L': '', 'top-M': '', 'top-R': '',
             'mid-L': '', 'mid-M': '', 'mid-R': '',
             'low-L': '', 'low-M': '', 'low-R': ''}
# print(the_board)

def print_board(board):
    print(board['top-L'] + '|' + board['top-M'] + '|' + board['top-R'])
    print('-+-+-')
    print(board['mid-L'] + '|' + board['mid-M'] + '|' + board['mid-R'])
    print('-+-+-')
    print(board['low-L'] + '|' + board['low-M'] + '|' + board['low-R'])

# print_board(the_board)

turn = 'X'
for i in range(9):
    print_board(the_board)
    move = input('把' + turn + '画在哪:')
    if move not in the_board.keys():
        print('请输入正确的位置')
        continue
    the_board[move] = turn
    if turn == 'X':
        turn = 'O'
    else:
        turn = 'X'
    if the_board['top-L'] == the_board['top-M'] == the_board['top-R'] == 'X' or the_board['mid-L'] == the_board['mid-M'] == the_board['mid-R'] == 'X' or the_board['low-L'] == the_board['low-M'] == the_board['low-R'] == 'X' or the_board['top-L'] == the_board['mid-L'] == the_board['low-L'] == 'X' or the_board['top-M'] == the_board['mid-M'] == the_board['low-M'] == 'X' or the_board['top-R'] == the_board['mid-R'] == the_board['low-R'] == 'X' or the_board['top-L'] == the_board['mid-M'] == the_board['low-R'] == 'X' or the_board['top-R'] == the_board['mid-M'] == the_board['low-L'] == 'X' :
        print('X，获胜')
        break
    elif the_board['top-L'] == the_board['top-M'] == the_board['top-R'] == 'O' or the_board['mid-L'] == the_board['mid-M'] == the_board['mid-R'] == 'O' or the_board['low-L'] == the_board['low-M'] == the_board['low-R'] == 'O' or the_board['top-L'] == the_board['mid-L'] == the_board['low-L'] == 'O' or the_board['top-M'] == the_board['mid-M'] == the_board['low-M'] == 'O' or the_board['top-R'] == the_board['mid-R'] == the_board['low-R'] == 'O' or the_board['top-L'] == the_board['mid-M'] == the_board['low-R'] == 'O' or the_board['top-R'] == the_board['mid-M'] == the_board['low-L'] == 'O':
        print('O,获胜')
        break
print_board(the_board)

**

```**

```

Answer 1

board = [[' ',' ',' '],[' ',' ',' '],[' ',' ',' ']]
s = 'XO' # 棋子符号，因为只有两个，所以我们用步数取2的余来确定落子方
step = 0 # 落子步数
while True:
    for row in range(3):
        if row > 0:
            print('-+-+-')
        print('|'.join(board[2 - row])) # 为了符合数字小键盘样子，我们反着输出行
    c = s[step % 2] # 获得当前落子方的棋子符号
    print('当前落子为{}'.format(c))
    n = input('输入落子位置（1-9），0退出本局：')
    if n.isnumeric() and n in '0123456789':
        n = int(n)
        if n == 0:
            print('你中断了本局游戏')
            break
        n -= 1
        board[n // 3][n % 3] = s[step % 2]
        # 行或列判断胜利
        if ''.join(board[n // 3]) == c * 3 or ''.join([row[n % 3] for row in board]) == c * 3:
            print('游戏结束，{}胜利'.format(c))
            break
        # 斜线判断胜利
        if board[0][0] + board[1][1] + board[2][2] == c * 3 or board[0][2] + board[1][1] + board[2][0] == c * 3:
            print('游戏结束，{}胜利'.format(c))
            break
        step += 1