用函数调用实现鸡兔同笼问题

Question

thonny用函数调用来实现鸡兔同笼问题，没有报错但是运行不了

原代码：def RC(heads,feet):
for i in range(0,heads+1):
j=heads-i
if feet-(i2)-(j4)==0:
print("chicken number",i)
print("rabbit number",j)
return[i,j]

RC(5,20)

Answer 1

def RC(heads,feet):
    for i in range(0,heads+1):
        j=heads-i
        if feet-(i*2)-(j*4)==0:
            print("chicken number",i)
            print("rabbit number",j)
            return[i,j]

RC(5,20)

缩进问题，把你的判断放到循环里