问一下,case:5 里面的 t=1 是什么意思,为什么要加上去这个,好像不加 t=1;
直接if(n==0);也一样。不明白有人能帮忙解答一下吗?
#include <stdio.h>
void main()
{
int oper1,oper2,choice ,s=0,x,i,n,t=1;
int sum,sub,mul;
double div;
char opnd;
printf("高级计算机\n");
printf("1.加法 2.减法");
printf("3.乘法 4.除非");
printf("5.累加和 6.阶乘\n");
scanf("%d",&choice);
if(choice>=1&&choice<=4)
{
printf("输入第一个操作数\n");
scanf("%d",&oper1);
printf("输入第二个操作数\n");
scanf("%d",&oper2);
}
switch(choice)
{
case 1:sum=oper1+oper2;
printf("%d+%d=%d\n",oper1,oper2,sum);
break;
case 2: sub=oper1-oper2;
printf("%d-%d=%d\n",oper1,oper2,sub);
break;
case 3: mul=oper1 * oper2;
printf("%d*%d=%d\n",oper1,oper2,mul);
break;
case 4: if(oper2!=0)
{
div=oper1/oper2;
printf("%d/%d=%d\n",oper1,oper2,div);
break;
}
else
printf("除数不能为0\n");
case 5: printf("输入求累计和的个数:\n");
scanf("%d",&n);
printf("请输入%d个数:\n",n);
if(n==0) t=1;
for(i=0;i<n;i++)
{
scanf("%d",&x);
s=s+x;
}
printf("%d个数的累计和=%d\n",n,s);
break;
case 6: printf("输入所求阶乘的数:\n");
scanf("%d",&n);
for(i=1;i<=n;i++)
t=t*i;
printf("%d!=%d\n",n,t);
break;
default:printf("选择错误!\n");
}
}