dongshan3759
2011-02-07 07:15 阅读 28
已采纳

将Bash命令转换为php

This is the bash command echo -n x && (echo 618cf954-6576-491d-8ac6-a1b888c4705d |xxd -r -p |openssl base64|tr '/+' '_-')

This is my php

<?
$uuid = "618cf954-6576-491d-8ac6-a1b888c4705d";
$voiceid = "x" . $uuid;
$voiceid  = base64_encode($voiceid);
$voiceid = str_replace("+", "-", $voiceid);
$voiceid = str_replace("/", "_", $voiceid);
echo $voiceid;
?>

The bash gives the right output, the php one isn't. I'm not sure what i need to do deferent in php.

The output should be xYYz5VGV2SR2KxqG4iMRwXQ==

A C++ version is at https://gist.github.com/1e096b658097c19cf309

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2条回答 默认 最新

  • 已采纳
    duanquanzhi5560 duanquanzhi5560 2011-02-07 07:18

    Also, in the Bash version, the "x" isn't included in the pipe through xxd and openssl. If you want it to be then do this:

    { echo -n x; echo -n 618cf954-6576-491d-8ac6-a1b888c4705d; } | xxd -r -p | openssl base64 | tr '/+' '_-')
    

    If, on the other hand, you want the PHP to match the existing Bash:

    <?
    $uuid = "618cf954-6576-491d-8ac6-a1b888c4
    $voiceid = str_replace("-", "", $uuid);
    $voiceid = pack("H*", $voiceid);
    $voiceid  = base64_encode($voiceid);
    $voiceid = str_replace("+", "-", $voiceid);
    $voiceid = str_replace("/", "_", $voiceid);
    $voiceid = "x" . $voiceid;
    echo $voiceid;
    ?>
    

    You will need to use pack to convert the hex string to binary.

    Edit: Fixed several of my errors.

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  • douzhuan1432 douzhuan1432 2011-02-07 07:25

    I think the following line is wrong:

    $voiceid = "x" . $uuid;
    

    Adding the "x" onto the string should be the last thing you do before the PHP echo.

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