将Bash命令转换为php

Question

This is the bash command echo -n x && (echo 618cf954-6576-491d-8ac6-a1b888c4705d |xxd -r -p |openssl base64|tr '/+' '_-')

This is my php

<?
$uuid = "618cf954-6576-491d-8ac6-a1b888c4705d";
$voiceid = "x" . $uuid;
$voiceid  = base64_encode($voiceid);
$voiceid = str_replace("+", "-", $voiceid);
$voiceid = str_replace("/", "_", $voiceid);
echo $voiceid;
?>

The bash gives the right output, the php one isn't. I'm not sure what i need to do deferent in php.

The output should be xYYz5VGV2SR2KxqG4iMRwXQ==

A C++ version is at https://gist.github.com/1e096b658097c19cf309

Answer 1

Also, in the Bash version, the "x" isn't included in the pipe through xxd and openssl. If you want it to be then do this:

{ echo -n x; echo -n 618cf954-6576-491d-8ac6-a1b888c4705d; } | xxd -r -p | openssl base64 | tr '/+' '_-')

If, on the other hand, you want the PHP to match the existing Bash:

<?
$uuid = "618cf954-6576-491d-8ac6-a1b888c4
$voiceid = str_replace("-", "", $uuid);
$voiceid = pack("H*", $voiceid);
$voiceid  = base64_encode($voiceid);
$voiceid = str_replace("+", "-", $voiceid);
$voiceid = str_replace("/", "_", $voiceid);
$voiceid = "x" . $voiceid;
echo $voiceid;
?>

You will need to use pack to convert the hex string to binary.

Edit: Fixed several of my errors.