使用休息显示细节

Question

using rest want to show the details about the items but there is a bug in the function code but according to me that is right but there is error in 7th line. i have two code they are as follow index.php

<?php
header("content-Type:application/json");
include("function.php");
if(!empty($_GET['name'])){

    $name = $_GET['name'];
    $price = get_price($name);

    if(empty($price))
        deliver_response(200,"book not found",NULL);
    else
        deliver_response(200,"book found",price);
}
else{
    deliver_response(400,"invalid",NULL);
}

function deliver_response($status,$status_message,$data)
{
    header("HTTP/1.1 $status $status_message");

    $response['status']=$status;
    $response['status_message']=$status_message;
    $response['data']=$data;

    $json_response=json_encode($response);
    echo $json_response;


}
?>

the function code

<?php
function get_price($find)
{
    $books = array(
        "java" => 300,
        "c"    => 250,
        "php"  => 350);
    for($books as $book => $price) {

        if($books == $find) {
            return $price;
            break;
        }
    }
}

?>

</div>

Answer 1

Use a foreach loop instead of a for loop and $book instead of $books in your if statement.

foreach ( $books AS $book => $price ) {
    if ( $book == $find ) {
        return $price;
    }
}