如何使用PHP正则表达式查找并返回字符串的一部分？

Question

I would like to find and return a sentence that starts with "Find" and ends with "eBay.", but I cannot get it to work. Here's what I have now:

if (preg_match("/^Find eBay\.$/", $post->post_content) == 1) {

                    $description = preg_grep("/^Find eBay\.$/", $post->post_content);

                } else {

                    $description = $this->trim_excerpt_without_filters($this->internationalize($post->post_content));

                }

Any advice would be great. Thanks!

Edit**

This is the string I'm searching:

<p><a href="http://cgi.ebay.com/ebaymotors/?cmd=ViewItem&amp;_trksid=p3984.m1438.l2649&amp;item=110804005978&amp;sspagename=STRK%3AMEWAX%3AIT">here on eBay</a>Find this 1969 Chevrolet Camaro COPO 427 for sale in New York, .</p>

Answer 1

try this, the .* means any number of any character

/^Find.*eBay\.$/