使用PHP，如何从以特定值开头的文本文件中回显一行？

Question

Lets say the text file " data1.txt" contains:

56715||Jim||Green||19  
5678||Sara||Red||92    
53676||Mark||Orange||6  
56787||Mike||Purple||123  
56479||Sammy||Yellow||645  
56580||Martha||Blue||952
ect...
.
.  

I would like to echo only the line beginning with "5678||". "5678" is the exact $refVal or reference value. The line should display like this:

My name is: $nameVar
My color is: $colorVar
My number is: $numVar

Thanks...

Answer 1

$fh = fopen('data1.txt', 'r') or die('Unable to open data1.txt');
while($line = fgetcsv($fh, 0, '||')) {
   if ($line[0] == 5678) {
       echo <<<EOL
My name is: $line[1]
My color is $line[2]
My number is $line[3]
EOL;
       break; // if there's only ever one '5678' line in the, get out now.
   }
}
fclose($fh);

---

alternate version, as suggested by Jared below. Probably will be faster, as it only does the array creation on the line that actually matches, and not for each line as the fgetcsv version does.

$fh = fopen('data1.txt', 'r') or die('Unable to open data1.txt');
while($line = fgets($fh)) {
   if (strpos($line, '5678||') === 0) { // only if right at start of string
        $data = explode('||', $line);
        echo <<<EOL
my name is blah blah blah 
EOL;
        break;
   }
}