doujiang1832 2011-04-02 16:21
浏览 37
已采纳

使用PHP中的换行符爆炸数据库内容不会创建数组

I've stored some values in my database which have linebreaks.

Wanting to transform those contents into an array, I did it like this:

$arr = explode($rs[data],"
");

Unfortunately this doesn't work. Any ideas as to what's wrong?

  • 写回答

2条回答 默认 最新

  • douwen9540 2011-04-02 16:22
    关注

    The parameters of your explode() call are inverted :

    • The first parameter should be the delimiter -- which will be used to explode the string
    • And the second parameter should be the string -- which will be exploded.


    So, you should use :

    $arr = explode("
    ", $rs[data]);
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥15 c语言怎么用printf(“\b \b”)与getch()实现黑框里写入与删除?
  • ¥20 怎么用dlib库的算法识别小麦病虫害
  • ¥15 华为ensp模拟器中S5700交换机在配置过程中老是反复重启
  • ¥15 java写代码遇到问题,求帮助
  • ¥15 uniapp uview http 如何实现统一的请求异常信息提示?
  • ¥15 有了解d3和topogram.js库的吗?有偿请教
  • ¥100 任意维数的K均值聚类
  • ¥15 stamps做sbas-insar,时序沉降图怎么画
  • ¥15 买了个传感器,根据商家发的代码和步骤使用但是代码报错了不会改,有没有人可以看看
  • ¥15 关于#Java#的问题,如何解决?