如何在php中为现有值添加值

Question

Consider my variable $result to be 01212.... Now if i add 1 to my variable i get the answer 1213,but i want it to be 01213.... My php code is

echo sprintf('%02u', ($result+1));

Edit:

Answers to this question works.. But what happens if my variable is $result to be 0121212 in future...

Answer 1

You can use %05u instead on %02u

echo sprintf('%05u', ($result+1));

EDIT:

To generalize it:

<?php

$result = "0121211";

$len = strlen($result+1) + 1;

printf("%0${len}d", ($result+1)); // print 0121212


?>