关于#python#的问题：求将上述代码编为pyqt中的槽函数

Question

def hist(img):
    [m,n]=img.shape
    out=[]
    a = 0
    for i in range(m):
        temp=0
        for j in range(n):
            temp=temp+img[i,j]
        out.append(temp)
    for i in range(m):
        if out[i]!=0:
            a=a+1

    return a


img = cv2.imread("")

求将上述代码编为pyqt中的槽函数，并且最后点击pushbutton能够输出的a在可视化窗口中输出显示出来。谢谢

Answer 1

import cv2
from PyQt5.QtCore import pyqtSlot, QObject


class MyObject(QObject):

    @pyqtSlot(str)
    def hist(self, img_path):
        img = cv2.imread(img_path)
        [m, n] = img.shape
        out = []
        a = 0
        for i in range(m):
            temp = 0
            for j in range(n):
                temp = temp + img[i, j]
            out.append(temp)
        for i in range(m):
            if out[i] != 0:
                a = a + 1
        return a