正则表达式 - 获取字符串中的所有匹配项

Question

I have a string like this:

$sContent = "t('Dashboard').' '.t('Settings Test').' '.t('My Test').' '.t('Other test')";

What I need is a regular expression that get each separate t('') values like:

t('Dashboard')
t('Settings Test')
...

In PHP I used:

$sRegExp = '/t\((.*)\)/i';
preg_match_all($sRegExp, $sContent, $aResults);

I get the same result with main string:

t('Dashboard').' '.t('Settings Test').' '.t('My Test').' '.t('Other test')

Answer 1

You can use:

$sRegExp = '/t\((.*?)\)/

or

$sRegExp = '/t\(([^\)]*)\)/